College

A 100-kg tackler moving at a speed of 2.7 m/s meets head-on (and holds on to) an 84-kg halfback moving at a speed of 5.0 m/s.

Answer :

Final answer:

This is a Physics problem dealing with the principle of momentum conservation in collisions. When two players collide and move together, their combined momentum after the collision equals their total initial momentum, resulting in a new shared velocity.

Explanation:

In this problem, two players collide and hold onto each other, forming a system that moves together. In such scenarios, the principle of momentum conservation applies. Momentum, a vector quantity, is the product of the mass and velocity of an object. Before the collision, the total momentum of the system is the vector sum of the individual momenta of the tackler and the halfback. As they collide and move together, their combined momentum after the collision should be equal to the total initial momentum.

The initial momentum of the tackler is 100 kg * 2.7 m/s = 270 kg*m/s, and that of the halfback is 84 kg * -5.0 m/s = -420 kg*m/s (the negative sign indicates the opposite direction of motion). Therefore, the total initial momentum is -150 kg*m/s. As per momentum conservation, their combined momentum post-collision (also this total momentum = -150 kg*m/s) split over the entire mass of 184 kg, gives the velocity they move together after the collision.

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