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------------------------------------------------ A 10 kg sack slides down a smooth surface. If the normal force on the surface at the flat spot, A, is 98.1 N (↑↑), the radius of the curvature is _____.

A. 0.2 m
B. 0.4 m
C. 1.0 m
D. None of the above

Answer :

The radius of the curvature is 1.0 m (option c) If the normal force on the surface at the flat spot, A is 98.1 N (↑↑) .

To calculate the radius of curvature using this formula:
radius of curvature (r) = (mass × acceleration due to gravity) / normal force

Step 1: Identify the mass (m), acceleration due to gravity (g), and normal force (N).
mass (m) = 10 kg
acceleration due to gravity (g) = 9.81 m/s²
normal force (N) = 98.1 N

Step 2: Plug in the values into the formula.
radius of curvature (r) = (10 kg × 9.81 m/s²) / 98.1 N

Step 3: Perform the calculations.
radius of curvature (r) = (98.1 kg m/s²) / 98.1 N

Step 4: Simplify the result.
radius of curvature (r) = 1 m

So, the radius of the curvature is 1.0 m .Hence, option c is correct.

To know more about Normal force refer here :

https://brainly.com/question/31377954

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