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------------------------------------------------ A 1 kg ball is thrown up in the air with a velocity of 9.9 m/s. Find the work done by its weight in 1 second.

A. 0 J
B. 49.05 J
C. -49.05 J
D. -98.1 J

The work done by the weight of the ball is equal to the change in gravitational potential energy. Using the formula ΔPE = mgh, the work done by the weight of the ball in 1 second is -98.1 J.

Explanation:

The work done by the weight of the ball is equal to the change in gravitational potential energy. The formula to calculate the change in gravitational potential energy is given by:

ΔPE = mgh

Where ΔPE is the change in gravitational potential energy, m is the mass (1 kg), g is the acceleration due to gravity (9.8 m/s²), and h is the height (the ball's initial height minus the ball's final height).

Using this formula, the work done by the weight of the ball in 1 second is given by:

ΔPE = (1 kg)(9.8 m/s²)(15 m - 5 m) = -98.1 J.