High School

A 1.3uF capacitor is connected to a 1.5 V battery. What is the charge on the capacitor? PREPARE Charge flows through the battery from one capacitor electrode to the other until the potential difference AVc between the electrodes equals that of the battery, or 1.5 V. SOLVE The charge on the capacitor is given by Equation 21.18: 2.0 x 10-6 C 0-CAVe (1.3 x 10-6 (1.5 v) ASSESS The small charge is expected for the small capacitance and the small voltage. and halve the potential difference, the new charge on the positive plate would be Value

Answer :

The new charge on the positive plate would be 9.75 x 10⁻⁷ C.

A capacitor is connected to a 1.5V battery and we need to calculate the charge on the capacitor.

Capacitance is 1.3µF.

The formula for calculating the charge on a capacitor is given as:

Q = CV

Where, Q = Charge on capacitor, C = Capacitance, and V = Voltage.

Substitute the given values in the above formula,

Q = (1.3 x 10⁻⁶) x (1.5)

Q = 1.95 x 10⁻⁶ C

The charge on the capacitor is 1.95 x 10⁻⁶ C.

To find the new charge on the positive plate when the potential

difference is halved, we can use the formula,

Q = CV

Substitute the given values in the above formula,

Q = (1.3 x 10⁻⁶) x (0.75)

Q = 9.75 x 10⁻⁷ C

The new charge on the positive plate would be 9.75 x 10⁻⁷ C.

To learn more about Capacitance from the given link.

https://brainly.com/question/21851402

#SPJ11

Other Questions