Answer :
The sum of the gravitational potential energy and kinetic energy of a 1.00-kg ball just before it hits the bottom of a 10.0-m deep well is 98 Joules, since all the gravitational potential energy would have been converted to kinetic energy. Therefore, the correct answer to the question is: O 98 J
The question is concerned with the concept of energy conservation, specifically the transformations between gravitational potential energy and kinetic energy as the ball falls. When the ball is dropped from a height of 10.0 meters and just before it hits the bottom of the well, its initial gravitational potential energy has been completely converted into kinetic energy, assuming there is no air resistance to take away some of the energy. The gravitational potential energy of an object at height h is given by PE = mgh, where m is the mass, g is the acceleration due to gravity (approximately 9.8 m/s2), and h is the height above the ground.
For a 1.00-kg ball dropped from 10.0 meters, the potential energy would be PE = (1.00 kg)(9.8 m/s2)(10.0 m) = 98 Joules.
Just before the ball hits the bottom, the sum of its kinetic and potential energy will still be equal to the initial potential energy since energy is conserved in the absence of external forces like air resistance. So, the correct answer is that the sum of the kinetic and potential energy is 98 J, and the potential energy just before impact would be approximately zero since it has been converted to kinetic energy.
