College

A 0.30-kg lead ball is heated to 90.0 °C and dropped into an ideal calorimeter containing 0.50 kg of water initially at 20.0 °C. What is the final equilibrium temperature of the lead ball? The specific heat capacity of lead is 128 J/(kg · C°); and the specific heat of water is 4186 J/(kg · C°).

Answer :

According to specific heat capacity and thermal equilibrium the final temperature of lead ball is 20°C.

What is specific heat capacity?

Specific heat capacity is defined as the amount of energy required to raise the temperature of one gram of substance by one degree Celsius. It has units of calories or joules per gram per degree Celsius.

It varies with temperature and is different for each state of matter. Water in the liquid form has the highest specific heat capacity among all common substances .Specific heat capacity of a substance is infinite as it undergoes phase transition ,it is highest for gases and can rise if the gas is allowed to expand.

It is given by the formula ,

Q=mcΔT

In the given problem at thermal equilibrium , the temperature of lead ball is found out as,m₁c₁Δt₁=m₂c₂Δt₂on substitution final temperature=0.3×1.28(T-20)=0.5×4186(T-20)=20°C

Thus the final temperature of lead ball is 20°C.

Learn more about specific heat capacity,here:

https://brainly.com/question/29766819

#SPJ2

Answer:

20.8° C

Explanation: