Answer :
Final answer:
Using the kinematic equation for vertical motion, the object projected vertically at 45 m/s will be approximately 103 meters above the ground after 4.3 seconds, corresponding to option 1).
Explanation:
To find out how high the 0.25 kg object is after 4.3 seconds when projected vertically with a velocity of 45 m/s, we can use the kinematic equation for vertical motion:
s = ut + ½ at²
where:
- s is the displacement (height in this context)
- u is the initial velocity
- t is the time
- a is the acceleration due to gravity (which is -9.81 m/s² since it's acting against the direction of motion)
Applying the formula, we get:
s = (45 m/s)(4.3 s) + ½ (-9.81 m/s²)(4.3 s)²
Calculate the values to get:
s = 193.5 m - 91.03645 m
s = 102.46355 m
Therefore, the object is about 103 meters above the ground after 4.3 seconds, which corresponds to option 1).
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