Answer :
Final answer:
To find the number of moles in 98.3 grams of Al(OH)3, divide the mass by the molar mass. The answer is 1.26 moles.
Explanation:
To find the number of moles in 98.3 grams of Al(OH)3, you need to use the formula:
Moles = Mass / Molar mass
First, calculate the molar mass of Al(OH)3. The atomic mass of aluminum (Al) is 26.98 g/mol, oxygen (O) is 16.00 g/mol, and hydrogen (H) is 1.01 g/mol. Since there are three oxygen atoms and three hydrogen atoms in Al(OH)3, you calculate the molar mass as:
(1 × 26.98 g/mol) + (3 × 16.00 g/mol) + (3 × 1.01 g/mol) = 78.00 g/mol
Now, plug the values into the formula:
Moles = 98.3 g / 78.00 g/mol = 1.26 mol
Therefore, there are 1.26 moles in 98.3 grams of Al(OH)3.
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