High School

7. Write down the short form of the following numbers given in the expanded form:(i) 60000 + 8000 + 900 + 90 + 1(ii) 2000 + 5(iii) 9000000 + 900 + 98. How many 6-digit numbers are there in all ?​

Answer :

The short forms of the given numbers are 68991, 2005, and 9000998. There are 3 6-digit numbers in total.

In the expanded form, we have the following numbers:

  1. 60000 + 8000 + 900 + 90 + 1
  2. 2000 + 5
  3. 9000000 + 900 + 98

(i) To write the short form, we simply add up the numbers. Therefore, the short form of the given expression is 60000 + 8000 + 900 + 90 + 1 = 68991.

(ii) Similarly, the short form of 2000 + 5 is 2005.

(iii) The short form of 9000000 + 900 + 98 is 9000998.

There are a total of 3 6-digit numbers in the given expressions.

Learn more about Short form of numbers here:

https://brainly.com/question/33537992

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