Answer :
After drawing one 20-watt bulb from a set of four, the probability of drawing another 20-watt bulb from the remaining three is 1/3 or approximately 0.33 which equates to a 33% chance.
In this problem, we are dealing with the concept of conditional probability. After drawing one 20-watt bulb from the second box, there are now 3 bulbs left in the box with one less 20-watt bulb.
Initially, we had 4 bulbs, of which 2 are 20 watts each (assuming an equal number of both types of bulbs were drawn) and 2 are 17 watts each. After drawing one 20-watt bulb, we're left with one 20-watt bulb and 2 of the 17-watt bulbs.
The probability of drawing another 20-watt bulb is the ratio of the number of 20-watt bulbs to the total number of bulbs left in the second box. In this case, it is 1 (20-watt bulbs) out of 3 (total bulbs). So, the probability is 1/3 or approximately 0.33 (33%).
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Final answer:
The probability of drawing a 20 Watt bulb again, after having drawn one already from the box without replacement, is 1 because all remaining bulbs are 20 Watt.
Explanation:
The subject of this question is probability, specifically concerning the drawing of bulbs from a box without replacement. To get the probability of picking a 20 Watt bulb twice consecutively from the second box, we need to consider the conditions being set. First, we have to understand that the first draw reduced the total number of 20 Watt bulbs to 3 (since the first 20 Watt bulb isn't replaced) from total of 4 bulbs.
Therefore, the probability of drawing a 20 Watt bulb again is calculated as the number of desired outcomes (3 remaining 20 Watt bulbs) divided by the total outcomes (remaining 3 bulbs in the box). This gives us a probability of 3 out of 3, or 1.
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