Answer :
Final answer:
The molarity of CaCl2 in the solution is 0.28 M. 0.028 moles of CaCl2 were added to the water. The mass of CaCl2 in the solution is 3.108 g.
Explanation:
To find the molarity of CaCl2 in the solution, we need to calculate the number of moles of CaCl2 and divide it by the volume of the solution in liters. The number of moles of CaCl2 can be found by dividing the mass of CaCl2 by its molar mass:
Moles of CaCl2 = (3.108 g / 111 g/mol) = 0.028 mol
Volume of water in liters = 1.0 deciliter = 0.1 liters
Therefore, the molarity of CaCl2 in the solution is:
Molarity = Moles of CaCl2 / Volume of solution = 0.028 mol / 0.1 L = 0.28 M
The moles of CaCl2 added to the water is 0.028 mol.
Mass of CaCl2 in the solution is 3.108 g.
