Answer :
Final answer:
To provide 12 mEq of sodium acetate in the PN order, 3 mL of 32.8% sodium acetate stock solution is required, after calculating based on the molecular weight and percentage concentration.
Explanation:
To calculate the volume of 32.8% sodium acetate stock solution required to prepare the parenteral nutrition (PN) order with 12 mEq of sodium acetate, first, the amount of sodium acetate in grams needs to be determined. Given that the molecular weight (M.W.) of sodium acetate is 82, and each mEq corresponds to a millimole for monovalent ions, we have 12 mEq which is equivalent to 12 mmol. Therefore, the mass of sodium acetate required is 12 mmol × 82 mg/mmol = 984 mg.
Now, knowing that the stock solution is 32.8% sodium acetate, we need to find out how many milliliters of this solution will have 984 mg of sodium acetate. Since 32.8% means 328 grams per 1000 mL, we can use a proportion to find the volume for 984 mg (0.984 grams):
0.984 g / x mL = 328 g / 1000 mL
Solving for x gives us:
x = (0.984 g × 1000 mL) / 328 g
x = 3 mL (rounded to the nearest whole number)
Therefore, 3 mL of the 32.8% sodium acetate stock solution is needed to provide 12 mEq of sodium acetate for the PN.
