Answer :
Final answer:
The combined milliequivalents of calcium and phosphorus in the Parenteral Nutrition order is 60 mEq/L.
Explanation:
To answer this question, we need to calculate the milliequivalents of calcium and phosphate in the Parenteral Nutrition (PN) order. Given that the quantity of calcium is 12 mEq and the quantity of phosphate is 24 mmol, we need to convert mmol of phosphate to mEq. We use the fact that 1 mmol of phosphate equals 2 mEq (as the question suggests), therefore, 24 mmol of phosphate equals 48 mEq.
Hence, the combined milliequivalents of calcium and phosphorus are the sum of 12 mEq of calcium and 48 mEq of phosphate, giving us 60 mEq/L total (which corresponds to answer option D).
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