College

190 students sit in an auditorium listening to a physics lecture. Each student is using 125 W of metabolic power. An air conditioner with a COP of 5.0 is keeping the room at a constant temperature.

What minimum electric power must be used to operate the air conditioner?

Answer :

Answer:

W = 4.75 KW

Explanation:

First, we will calculate the heat to be removed:

Q = (No. of students)(Metabolic Power of Each Student)

Q = (190)(125 W)

Q = 23750 W = 23.75 KW

Now the formula of COP is:

[tex]COP = \frac{Q}{W}\\\\W = \frac{Q}{COP}\\\\W = \frac{23.75\ KW}{5}\\\\[/tex]

W = 4.75 KW

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