High School

18 grams of ice is converted into water at 0°C and 1 atm. The entropy of H₂ and H₂O is 38.2 J/mol·K and 60 J/mol·K, respectively. The enthalpy for this conversion is:

A. 595.14 J/mol
B. 595.14 J/mol
C. -595.14 J/mol
D. None of these

Answer :

Final answer:

The enthalpy change for the conversion of ice to water at 0°C and 1 atm can be calculated using the equation ΔH = ΔS. Given the provided entropies of H₂ and H₂O, we can calculate the entropy change. However, without information about the enthalpy of H₂ and H₂O, we cannot determine the exact enthalpy change.

Therefore the correct answer is D). None of these

Explanation:

The enthalpy change for the conversion of ice to water at 0°C and 1 atm can be calculated using the equation:

ΔH = ΔS

Where ΔH is the enthalpy change and ΔS is the entropy change. Given that the entropy of H₂ is 38.2 J/mol K and the entropy of H₂O is 60 J/mol K, we can calculate the entropy change of the conversion as follows:

ΔS = ΔSproducts - ΔSreactants = 60 J/mol K - 38.2 J/mol K = 21.8 J/mol K

Since the question asks for the enthalpy change, not the entropy change, and does not provide information about the enthalpy of H₂ or H₂O, we cannot calculate the exact enthalpy change using the given information. Therefore, the correct answer is D. None of these.