College

15. Which equation, when solved, results in a different value of [tex]$x$[/tex] than the other three?

Show your work:

A. [tex]8.3 = -0.6 x + 11.3[/tex]

B. [tex]11.3 = 8.3 + 0.6 x[/tex]

C. [tex]11.3 - 0.6 x = 8.3[/tex]

D. [tex]8.3 - 0.6 x = 11.3[/tex]

Answer :

To solve the problem, we need to determine which equation results in a different value of [tex]\( x \)[/tex] compared to the others. Let's solve each equation one by one:

### Equation A:

[tex]\[ 8.3 = -0.6x + 11.3 \][/tex]

1. Subtract 11.3 from both sides to isolate terms with [tex]\( x \)[/tex]:

[tex]\[ 8.3 - 11.3 = -0.6x \][/tex]

2. Simplify:

[tex]\[ -3 = -0.6x \][/tex]

3. Divide both sides by -0.6 to solve for [tex]\( x \)[/tex]:

[tex]\[ x = \frac{-3}{-0.6} = 5 \][/tex]

### Equation B:

[tex]\[ 11.3 = 8.3 + 0.6x \][/tex]

1. Subtract 8.3 from both sides:

[tex]\[ 11.3 - 8.3 = 0.6x \][/tex]

2. Simplify:

[tex]\[ 3 = 0.6x \][/tex]

3. Divide by 0.6:

[tex]\[ x = \frac{3}{0.6} = 5 \][/tex]

### Equation C:

[tex]\[ 11.3 - 0.6x = 8.3 \][/tex]

1. Subtract 11.3 from both sides:

[tex]\[ -0.6x = 8.3 - 11.3 \][/tex]

2. Simplify:

[tex]\[ -0.6x = -3 \][/tex]

3. Divide by -0.6:

[tex]\[ x = \frac{-3}{-0.6} = 5 \][/tex]

### Equation D:

[tex]\[ 8.3 - 0.6x = 11.3 \][/tex]

1. Subtract 8.3 from both sides:

[tex]\[ -0.6x = 11.3 - 8.3 \][/tex]

2. Simplify:

[tex]\[ -0.6x = 3 \][/tex]

3. Divide by -0.6:

[tex]\[ x = \frac{3}{-0.6} = -5 \][/tex]

Now that we have solved all the equations, we can see the solutions are:

- Equation A gives [tex]\( x = 5 \)[/tex]
- Equation B gives [tex]\( x = 5 \)[/tex]
- Equation C gives [tex]\( x = 5 \)[/tex]
- Equation D gives [tex]\( x = -5 \)[/tex]

The equation that results in a different value of [tex]\( x \)[/tex] is Equation D.