High School

15. For the equilibrium established below A(g)⟺B(g) has equilibrium constant K_c​ =0.50. Suppose the initial concentration of A(g) is 1.0M and that of B(g) is 0.0M. What will be the concentration of B(g) when the system reaches equilibrium? a) 0.50M b) 0.33M c) 1.0M d) 0.25M e) 1.5M

Answer :

Final answer:

The concentration of B(g) when the system reaches equilibrium is 0.50M.

Explanation:

To find the concentration of B(g) at equilibrium, we can use the equilibrium constant expression:

Kc = [B(g)] / [A(g)]

Given that the initial concentration of A(g) is 1.0M and that of B(g) is 0.0M, we can substitute these values into the equation:

0.50 = [B(g)] / 1.0

Cross-multiplying, we get:

[B(g)] = 0.50 * 1.0

[B(g)] = 0.50M

Therefore, the concentration of B(g) when the system reaches equilibrium is 0.50M.

Learn more about equilibrium constant here:

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