High School

13. Marsean solved the following quadratic equation but did not end up with the correct answer. Find his mistake, circle the line where the mistake was made, and correct it to get the correct answer of [tex]x=\frac{2}{5}[/tex].

[tex]
\begin{array}{l}
1. \quad 25x^2 = 20x - 4 \\
2. \quad 25x^2 - 20x + 4 = 0 \\
3. \quad a = 25, \; b = -20, \; c = 4 \\
4. \quad x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \\
5. \quad x = \frac{-(-20) \pm \sqrt{(-20)^2 - 4(25)(4)}}{2(25)} \\
6. \quad x = \frac{20 \pm \sqrt{400 - 400}}{50} \\
7. \quad x = \frac{20 \pm \sqrt{0}}{50} \\
8. \quad x = \frac{20 \pm 0}{50} \\
9. \quad x = \frac{20}{50} \\
10. \quad x = \frac{2}{5}
\end{array}
[/tex]

- Mistake found in Line 5. The correct line should read:
[tex]5. \quad x = \frac{-(-20) \pm \sqrt{(-20)^2 - 4(25)(4)}}{2(25)}[/tex]

- Correction is needed in Line 6. The correct calculation should read:
[tex]6. \quad x = \frac{20 \pm \sqrt{400 - 400}}{50}[/tex]

- Continue with the correct calculation to reach the correct solution in Line 9 and Line 10:
[tex]9. \quad x = \frac{2}{5}[/tex]

Answer :

Let's go through Marsean's solution step-by-step to identify and correct the mistake:

1. Original Equation:

[tex]\( 25x^2 = 20x - 4 \)[/tex]

2. Rearrange into Standard Quadratic Form:

[tex]\( 25x^2 - 20x + 4 = 0 \)[/tex]

3. Coefficients:

[tex]\( a = 25 \)[/tex], [tex]\( b = -20 \)[/tex], [tex]\( c = 4 \)[/tex]

4. Quadratic Formula:

The quadratic formula is:

[tex]\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\][/tex]

5. Discriminant Calculation:

Let's calculate the discriminant, which is the part under the square root:

[tex]\( b^2 - 4ac = (-20)^2 - 4 \cdot 25 \cdot 4 \)[/tex]

6. Calculate Discriminant:

[tex]\( = 400 - 400 = 0 \)[/tex]

Here is where Marsean made a mistake. The discriminant was calculated as [tex]\(-800\)[/tex] in his work, which was incorrect.

7. Square Root of the Discriminant:

Since the corrected discriminant is 0:

[tex]\(\sqrt{0} = 0\)[/tex]

8. Plug Back into the Quadratic Formula:

[tex]\[
x = \frac{-(-20) \pm 0}{2 \cdot 25} = \frac{20 \pm 0}{50}
\][/tex]

9. Simplify the Expression:

[tex]\[
x = \frac{20}{50} = \frac{2}{5}
\][/tex]

The correct solution shows that there is a single real solution, [tex]\( x = \frac{2}{5} \)[/tex], not a complex one as originally stated. Therefore, the mistake was in calculating the discriminant incorrectly as [tex]\(-800\)[/tex] instead of [tex]\(0\)[/tex], and consequently finding complex solutions instead of a real solution.