Answer :
Final answer:
The final volume of the gas at 99.3 kPa and 112.3°C is calculated using the combined gas law and the correct answer is 101 ml.
Explanation:
The subject of this question is Chemistry, and it appears to be at a High School level. The student is asking for the final volume of a gas when subjected to differing pressures and temperatures. This type of question involves applying the combined gas law, which connects pressure, volume, and temperature in the following relationship:
P1V1/T1 = P2V2/T2,
where P1 and V1 are the initial pressure and volume, T1 is the initial temperature, P2 and V2 are the final pressure and volume, and T2 is the final temperature. Since temperatures must be in Kelvin for this law to be applied accurately, we first convert temperatures from ℃ to K:
- T1 = 57.2℃ + 273.15 = 330.35 K
- T2 = 112.3℃ + 273.15 = 385.45 K
Then, we plug in the given values into the combined gas law:
(45.8 kPa)(115 mL) / (330.35 K) = (99.3 kPa)(V2) / (385.45 K)
Solving for V2, we get:
V2 = (45.8 kPa)(115 mL)(385.45 K) / (99.3 kPa)(330.35 K) ≈ 101 mL
Therefore, the correct answer is (a) 101 ml.
