Answer :
Final answer:
The volume of the gas under the given conditions can be calculated using the combined gas law. After necessary unit conversions, we find that the volume of gas at 99.3 kPa and 112.3°C is approximately 135 mL, making the correct choice (C) 135 mL.
Explanation:
The question revolves around the application of the combined gas law. This law, in the world of physics, allows us to understand how gases behave under different conditions. The combined gas law states that the ratio of the product of pressure and volume to temperature of one state is equal to the ratio of the product of pressure and volume to temperature of another state.
Let’s denote the initial state of the gas with P1, V1, and T1 (pressure, volume, and temperature, respectively) and the final state with P2, V2, and T2.
According to the combined gas law: (P1 * V1)/T1 = (P2 * V2)/T2
In this specific question:
- P1 is 45.8 kPa
- V1 is 115 mL
- T1 is 57.2°C (which you would first need to convert to Kelvin by adding 273 to get T1 = 330.2 K)
- P2 is 99.3 kPa
- T2 is 112.3°C (which again, needs to be converted to Kelvin to get T2 = 385.3 K)
We plug these values into the combined gas law equation and solve for V2. As a result, 'The volume of the gas at 99.3 kPa and 112.3°C is approximately 135 mL.', which makes the correct choice (C) 135 mL.
Learn more about Combined Gas Law here:
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