High School

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------------------------------------------------ 1. Solve the inequality: [tex]\frac{x}{3} \leq 21[/tex]

A. 96
B. 84
C. 63
D. 66

2. What is the temperature if it is 9 degrees colder than [tex]-15^{\circ} F[/tex]?

A. [tex]24^{\circ} F[/tex]
B. [tex]6^{\circ} F[/tex]
C. [tex]-6^{\circ} F[/tex]
D. [tex]-24^{\circ} F[/tex]

Answer :

We begin with the inequality:
[tex]$$
\frac{x}{3} \leq 21.
$$[/tex]

Step 1. Multiply both sides by 3:
Multiplying both sides of the inequality by 3 gives
[tex]$$
x \leq 21 \times 3.
$$[/tex]

Step 2. Simplify the result:
Calculating the right-hand side, we get
[tex]$$
x \leq 63.
$$[/tex]
This means that the largest possible value of [tex]$x$[/tex] is [tex]$63$[/tex]. Therefore, the answer to the first question is [tex]$\boxed{63}$[/tex] (option C).

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Next, we address the temperature problem.

Step 1. Understand the problem:
It is stated that the temperature is [tex]$9^\circ F$[/tex] colder than [tex]$-15^\circ F$[/tex]. “Colder” means we subtract [tex]$9^\circ F$[/tex] from [tex]$-15^\circ F$[/tex].

Step 2. Perform the subtraction:
[tex]$$
-15^\circ F - 9^\circ F = -24^\circ F.
$$[/tex]

Thus, the temperature is [tex]$-24^\circ F$[/tex]. Therefore, the answer to the second question is [tex]$\boxed{-24^\circ F}$[/tex] (option D).

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Final Answers:
1. [tex]$\displaystyle \frac{x}{3} \leq 21$[/tex] has a maximum value of [tex]$x = 63$[/tex] (Option C).
2. The temperature is [tex]$-24^\circ F$[/tex] (Option D).