Answer :
Let's work through each part of the question:
Counting the number of digits in each number:
(a) 10000 (Ten thousand):
The number 10000 has 5 digits. This is because each place (ones, tens, hundreds, thousands, ten thousands) contains a digit, and the digits are 1 followed by four 0s.
(b) 50000 (Fifty thousand):
The number 50000 also has 5 digits. It follows the same reasoning as above, starting with a 5 followed by four zeros.
(c) 90000 (Ninety thousand):
The number 90000 has 5 digits. Similar to the previous numbers, it starts with a 9 followed by four zeros.
Counting by 10 thousands and filling in the missing numerals:
(a) 10000, 20000, 30000, ______, 60000
The sequence increases by 10000 each time. So, after 30000, the next number should be 40000, then 50000, and finally 60000. The missing number is 40000.
(b) 70000, ______, 90000, then ______
Again, the sequence increases by 10000. After 70000, the next number should be 80000, and after 90000, the next would be 100000. The missing numbers are 80000 and 100000.
I hope this helps! Let me know if you have any other questions.
