High School

1. How many minutes are there in 4 hours?
2. Rewrite in descending order 560, 735, 230, 239.
3. Take away the number of days in the month of June from the number of days in the month of October.
4. How many 50 paisa coins are there in ₹.9.50 P?
5. 7 x (5 x 5) =
6. From 9 x 5 take away 8 x 4 =
7. In number 7605, the digit in the hundreds place is.
8. The successor of the smallest 4 digit numeral is.
9. 4809 is one less than.
10. 100 more than 5785 is.
11. At half past seven, minutes hand will be at.
12. Add the sum of 15 and 45 to 60.

Answer :

  1. To determine how many minutes there are in 4 hours, you multiply the number of hours by the number of minutes in one hour.\n\n [tex]4 \text{ hours} \times 60 \text{ minutes/hour} = 240 \text{ minutes}[/tex]\n\n2. To rewrite the numbers 560, 735, 230, and 239 in descending order, you arrange them from highest to lowest. So, the order will be: 735, 560, 239, 230.\n\n3. June has 30 days and October has 31 days. So, take away the number of days in June from October:\n\n [tex]31 - 30 = 1[/tex]\n\n4. To find how many 50 paisa coins make up ₹9.50, you first convert the rupees into paisa. ₹9.50 is the same as 950 paisa. Since each coin is worth 50 paisa:\n [tex]\frac{950}{50} = 19\text{ coins}[/tex]\n\n5. To solve [tex]7 \times (5 \times 5)[/tex], first calculate the expression inside the parentheses:\n [tex]5 \times 5 = 25[/tex]\n Then multiply by 7:\n [tex]7 \times 25 = 175[/tex]\n\n6. For the calculation, from [tex]9 \times 5[/tex] take away [tex]8 \times 4[/tex]:\n [tex]9 \times 5 = 45[/tex] \n [tex]8 \times 4 = 32[/tex]\n [tex]45 - 32 = 13[/tex]\n\n7. In the number 7605, the digit in the hundreds place is 6.\n\n8. The smallest 4-digit numeral is 1000. Adding 1 to find the successor, we get 1001.\n\n9. The number 4809 is one less than 4810.\n\n10. Adding 100 more to 5785 gives:\n [tex]5785 + 100 = 5885[/tex]\n\n11. At half past seven, the minute hand will be on 6 on the clock, which represents 30 minutes past the hour.\n\n12. Adding the sum of 15 and 45 to 60:\n [tex]15 + 45 = 60[/tex] \n [tex]60 + 60 = 120[/tex]