Answer :
Final answer:
The magnitude and direction of the force on the charges are as follows:
a) -5.00 μC charge: The force is 44.95 N and directed away from the +1.00 μC charge.
b) +5.00 μC charge: The force is 44.95 N and directed towards the -1.00 μC charge.
Explanation:
To find the magnitude and direction of the force on the given charges, we can use Coulomb's Law. Coulomb's Law states that the force between two charges is given by:
F = k * (|q1| * |q2|) / r^2
Where:
- F is the magnitude of the force
- k is the electrostatic constant (k = 8.99 x 10^9 Nm^2/C^2)
- |q1| and |q2| are the magnitudes of the charges
- r is the distance between the charges
Let's calculate the force for each charge:
a) -5.00 μC charge:
Since the charge is negative, we know that it will repel other negative charges and attract positive charges. Let's assume there is a +1.00 μC charge at a distance of 1 meter from the -5.00 μC charge. Plugging the values into Coulomb's Law:
F = (8.99 x 10^9 Nm^2/C^2) * ((5.00 x 10^-6 C) * (1.00 x 10^-6 C)) / (1 m)^2
Simplifying the equation:
F = 44.95 N
The magnitude of the force on the -5.00 μC charge is 44.95 N, and it is directed away from the +1.00 μC charge.
b) +5.00 μC charge:
Since the charge is positive, we know that it will attract negative charges and repel positive charges. Let's assume there is a -1.00 μC charge at a distance of 1 meter from the +5.00 μC charge. Plugging the values into Coulomb's Law:
F = (8.99 x 10^9 Nm^2/C^2) * ((5.00 x 10^-6 C) * (1.00 x 10^-6 C)) / (1 m)^2
Simplifying the equation:
F = 44.95 N
The magnitude of the force on the +5.00 μC charge is 44.95 N, and it is directed towards the -1.00 μC charge.
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