Answer :
1. The equivalent resistance of a 10 Ohm resistor and a 4 Ohm resistor wired in series is 14 Ohms.
2. The voltage drop across the 10 Ohm resistor, when connected to a 5 V battery, is 3.6 V.
3. The current flowing through the 10 Ohm resistor, when connected to a 5 V battery, is 0.36 A.
1. When resistors are connected in series, the equivalent resistance is the sum of individual resistances. Therefore, the equivalent resistance of a 10 Ohm resistor and a 4 Ohm resistor wired in series is 10 Ohms + 4 Ohms = 14 Ohms.
2. In a series circuit, the total voltage of the battery is distributed across the resistors. Since the resistors are connected in series, the same current flows through both resistors. The voltage drop across a resistor can be calculated using Ohm's law:
[tex]V = I * R[/tex]
where V is the voltage, I is the current, and R is the resistance. Given a 5 V battery and a total resistance of 14 Ohms, the voltage drop across the 10 Ohm resistor can be calculated as follows:
[tex]V_{10 }= (10 \ Ohms / 14\ Ohms) * 5\ V = 3.6\ V[/tex]
3. In a series circuit, the current remains constant throughout. The current flowing through the resistors can be calculated using Ohm's law: I = V / R, where I is the current, V is the voltage, and R is the resistance. Given a 5 V battery and a total resistance of 14 Ohms, the current flowing through the circuit is: I = 5 V / 14 Ohms = 0.36 A. Since the same current flows through both resistors in a series circuit, the current flowing through the 10 Ohm resistor is also 0.36 A.
Learn more about Ohm's law here:
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