Answer :
The value of the equilibrium constant is 6.25.
To calculate the equilibrium constant, we need to use the balanced chemical equation and the Law of Mass Action. The balanced chemical equation for the reaction is:
CO(g) + H2O(g) ⇌ CO2(g) + H2(g)
The Law of Mass Action expression for this reaction is:
Kc = [CO2][H2]/[CO][H2O]
where Kc is the equilibrium constant, and the square brackets denote molar concentrations.
From the given information, we know that:
[CO] = 1.60 moles/8.00 L = 0.20 M
[H2O] = 1.60 moles/8.00 L = 0.20 M
[CO2] = 4.00 moles/8.00 L = 0.50 M
[H2] = 4.00 moles/8.00 L = 0.50 M
Substituting these values into the Law of Mass Action expression gives:
Kc = (0.50)(0.50)/(0.20)(0.20) = 6.25
Therefore, the value of the equilibrium constant is 6.25.
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