**1.3 Temperature Increase due to Incandescent Lighting**

When energy is added to a fluid, the temperature of the fluid increases. An equation describing this phenomenon is:

\[ Q = M C \Delta T \]

Where:
- \( Q \) is the amount of energy added (joules)
- \( M \) is the mass of the fluid (kg)
- \( C \) is the heat capacity of the fluid (joules/kg·K)
- \( \Delta T \) is the change in temperature (K, or °C)

A garage (24 ft x 24 ft x 10 ft) is illuminated by six 60W incandescent bulbs. It is estimated that 90% of the energy to an incandescent bulb is dissipated as heat. If the bulbs are on for 3 hours, how much would the temperature in the garage increase because of the light bulbs (assuming no energy losses)?

Complete an Excel worksheet like the one illustrated in Figure 1.71 to answer this question.

### Specified Information
- Number of Bulbs: 6
- Bulb Power: 60 W
- Bulb Percent Power Lost as Heat: 90%
- Bulbs on Time: 3 hrs
- Garage Air Volume: 5760 ft³
- Air Density: 1.2 kg/m³
- Air Heat Capacity: 1000 joules/kg·K

**Useful Information**
- Air density: 1.2 kg/m³
- Air heat capacity: 1000 joules/kg·K
- Length conversion: 3.28 ft = 1 m

### Calculated Information
- Total Bulb Power:
- Total Bulb Power Lost as Heat:
- Total Bulb Power Lost as Heat (joules/second):
- Total Bulb Energy Lost as Heat (joules):
- Garage Air Volume (m³):
- Garage Air Mass (kg):
- Temperature Change (K):

### Hints:
- Consider the number of bulbs.
- Consider the total bulb power and percent power lost.
- Convert the time units.
- Unit conversion (volume * density).
- Energy lost divided by (air mass * air heat capacity).

Complete the table to determine the temperature change in the garage due to the incandescent lighting.