Answer :
Final answer:
The change in entropy (ΔS°) for species A in the reaction 3A → 2B is -92.7 J/mol·K.
Explanation:
To determine the change in entropy (ΔS°) for species A in the reaction 3A → 2B, we need to use the equation ΔS°(rxn) = ΔS°(B) - ΔS°(A). We are given ΔS°(rxn) = -147.3 J/mol·K and ΔS°(B) = 240.0 J/mol·K.
Substituting these values into the equation, we have -147.3 J/mol·K = 240.0 J/mol·K - ΔS°(A). To solve for ΔS°(A), we rearrange the equation to get ΔS°(A) = -240.0 J/mol·K - (-147.3 J/mol·K). Simplifying, we find ΔS°(A) = -92.7 J/mol·K.
