High School

The freezing point of an aqueous solution of MgBr₂ was found to be -5.7 °C. Calculate the boiling point of an aqueous solution of AlCl₃ that has the same molality as the MgBr₂ solution.

Given:
- [tex]K_f[/tex] for water = 1.86 °C/m
- [tex]K_b[/tex] for water = 0.512 °C/m

Possible answers:
A. 101.1 °C
B. 102.1 °C
C. 99.9 °C
D. 100.5 °C
E. 101.5 °C

Answer :

The boiling point of an aqueous solution of AlCl3 with the same molality as the MgBr2 solution is 102.1 °C.

To calculate the boiling point of the aqueous solution of AlCl3, we can use the equation:

ΔTb = K_b * m.

Since the freezing point of the MgBr2 solution is given, we can find its molality using the equation:

ΔTf = K_f * m.

Rearranging the equation gives us the molality of MgBr2.

Now, we can use this molality value to calculate the boiling point of the AlCl3 solution.

Since the molality of the AlCl3 solution is the same as the molality of the MgBr2 solution, we can use the same molality value found for MgBr2 to calculate the boiling point elevation for the AlCl3 solution.

Plugging in the values into the equation ΔTb = K_b * m, we get the boiling point elevation for the AlCl3 solution.

Adding this boiling point elevation to the boiling point of pure water gives us the boiling point of the AlCl3 solution.

Therefore, the boiling point of an aqueous solution of AlCl3 with the same molality as the MgBr2 solution is 102.1 °C.

Learn more about the topic of aqueous solution here:

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