High School

The coefficient of performance of an air conditioner is 2.5. The work done by the motor is 60 J. How much energy is removed from the room it cools?

A. 250 J
B. 120 J
C. 160 J
D. 150 J

Answer :

The amount of energy removed from the room by the air conditioner is 150J (option d).

To decide how much energy eliminated from the room by the climate control system, we can utilize the coefficient of performance (COP) and the work done by the engine.

The coefficient of execution (COP) is characterized as the proportion of the intensity moved (energy eliminated) from the space to the work done by the engine. For this situation, the COP is given as 2.5.

COP = Intensity Moved/Work Done

We are given that the work done by the engine is 60 J. Utilizing the COP equation, we can modify it to settle for the intensity moved:

Heat Moved = COP * Work Done

Subbing the given qualities:

Heat Moved = 2.5 * 60 J = 150 J

Subsequently, how much energy eliminated from the room by the forced air system is 150 J. The right response is d. 150J.

To learn more about coefficient of performance (COP), refer:

https://brainly.com/question/14182691

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