High School

Resistances of 2.1 Ω, 4.9 Ω, and 6 Ω and a 26.4 V battery are all in series. Find the potential difference across the first (2.1 Ω) resistor. Answer in units of V.

Answer :

The correct answer is the potential difference across the first resistor is 4.26 V.

To find the potential difference across the first resistor, we need to use Ohm's law, which states that V = IR, where V is the potential difference (in volts), I is the current (in amperes), and R is the resistance (in ohms).


Since the resistances are all in series, the total resistance is simply the sum of the individual resistances: 2.1 ω + 4.9 ω + 6 ω = 13 ω.


To find the current, we use the equation I = V/R, where V is the battery voltage (26.4 V) and R is the total resistance (13 ω). Therefore, I = 26.4 V / 13 ω = 2.03 A.


Finally, we can use Ohm's law to find the potential difference across the first resistor: V = IR = 2.03 A x 2.1 ω = 4.26 V.

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