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------------------------------------------------ How many grams of sucrose (C₁₂H₂₂O₁₁) are in 1.55 L of a 0.758 M sucrose solution?

The mass of sucrose in 1.55 L of a 0.758 M sucrose solution can be found by first determining the moles of sucrose present and then converting those moles to grams using the molar mass of sucrose. The calculation yields approximately 401.93 grams of sucrose in the solution.

The student is asking about the mass of sucrose in a specific volume of a sucrose solution with a given molarity. To find the number of grams of sucrose in a 1.55 L solution of 0.758 M sucrose, we first need to calculate the moles of sucrose present in the solution using the molarity (mol/L) and the volume of the solution (L). After calculating the number of moles of sucrose, we can then find the mass in grams using the molar mass of sucrose (C12H22O11), which is 342.30 g/mol.

Calculate the moles of sucrose: 1.55 L \$ imes\$ 0.758 mol/L = 1.1749 mol.
Calculate the mass of sucrose: 1.1749 mol \$ imes\$ 342.30 g/mol = 401.93 grams of sucrose.

This result provides the mass of sucrose in the given volume of the solution.