Find the number of protons, neutrons, and electrons, as well as the mass number, given a charge of 0 and a complete atomic designation \(\frac{207}{82}\text{Pb}\).

A. Protons: 82, Neutrons: 125, Electrons: 82, Mass Number: 207

B. Protons: 82, Neutrons: 125, Electrons: 125, Mass Number: 207

C. Protons: 125, Neutrons: 82, Electrons: 82, Mass Number: 207

D. Protons: 125, Neutrons: 82, Electrons: 125, Mass Number: 207

The atomic designation 207/82Pb indicates that this atom of lead has an atomic number of 82 (protons), a mass number of 207 (protons + neutrons), and because it is neutral (charge 0), it also has 82 electrons. The number of neutrons is found by subtracting the atomic number from the mass number (207 - 82 = 125 neutron).

Explanation:

The correct answer is option a. Protons: 82, Neutrons: 125, Electrons: 82, Mass Number: 207. The number of protons in an atom is its atomic number, represented by the number 82 in the atomic designation 207/82Pb. The mass number is the sum of the numbers of protons and neutrons in the nucleus, which here is 207.

To find the number of neutrons, you subtract the atomic number from the mass number (207 - 82 = 125). As the charge is zero, indicating a neutral atom, the atom must have an equal number of protons and electrons, so the number of electrons is also 82.

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