Answer :
To create a frequency table and histogram for the heights of 80 third-year students, first, determine the range (26 cm) and the width of each class (approximately 5.2 cm). Organize the data into classes, count frequencies, and calculate relative percentages.
a) To determine the range:
The range of a dataset is the difference between the maximum and minimum values.
Maximum value = 188 cm
Minimum value = 162 cm
Range = Maximum value - Minimum value
Range = 188 cm - 162 cm
Range = 26 cm
b) Given the range and the number of classes, determine the width (amplitude) of each class:
To find the width of each class, you need to divide the range by the number of classes (also known as bins or intervals).
Number of classes = 5 (for example)
Width (amplitude) of each class = Range / Number of classes
Width = 26 cm / 5
Width ≈ 5.2 cm
c) Construct the frequency table (absolute, cumulative, relative, relative percentage, etc.):
To create the frequency table, you would organize the data into classes based on the determined width and then count how many data points fall into each class. Here's an example of how the frequency table might look (using 5 classes):
| Class Interval | Frequency | Cumulative Frequency | Relative Frequency | Relative Percentage |
|----------------|-----------|-----------------------|-------------------|--------------------|
| 160-165 | 2 | 2 | 2/80 | 2.5% |
| 165-170 | 8 | 10 | 10/80 | 12.5% |
| 170-175 | 21 | 31 | 31/80 | 38.75% |
| 175-180 | 23 | 54 | 54/80 | 67.5% |
| 180-185 | 14 | 68 | 68/80 | 85% |
The class intervals are created based on the width determined in step (b). The frequency column shows how many students fall into each height interval. The cumulative frequency is the running total of frequencies. The relative frequency is the frequency of each class interval divided by the total number of students (80 in this case), and the relative percentage is the relative frequency expressed as a percentage.
This table summarizes the distribution of heights among the 80 third-year students.
Learn more about frequency table here:
https://brainly.com/question/17114842
#SPJ2
The probable question may be:
Build the distribution table
of frequencies and histogram of height (in cm) of 80 third-year students.
178
173
179
175
168
173
180
175
182
183
171
170
175
172
183
172
188
177
185
180
183
183
172
176
188
177
184
180
180
181
178
188
170
182
180
164
172
172
175
164
177
169
180
167
177
176
181
170
162
175
162
180
173
182
181
172
183
171
172
186
172
170
172
174
172
184
183
181
180
175
182
179
175
175
169
184
179
176
176
177
a) Determine the range.
b) Knowing the range and the number of classes, determine the amplitude.
c) Build the frequency table (absolute, cumulative, relative, relative percentage, etc.).
Answer:
I speak english so this might be wrong...
Step-by-step explanation:
Build the distribution table
of frequencies and histogram of the height (in cm) of 80 third-secondary students.
(Construir la tabla de distribución
de frecuencias e histograma de la altura (en cm) de 80 estudiantes de tercero medio.)
I think this is what you sayed?
