Answer :
When acetone reacts with a Grignard reagent, the typical product formed is a tertiary (3º) alcohol.
Here's a step-by-step explanation of the reaction:
Starting Materials: Acetone is a simple ketone with the formula [tex]\text{C}_3\text{H}_6\text{O}[/tex] or [tex]\text{CH}_3\text{COCH}_3[/tex]. A Grignard reagent has the general formula [tex]\text{R-MgX}[/tex], where [tex]\text{R}[/tex] is an alkyl or aryl group and [tex]\text{X}[/tex] is a halogen (commonly chlorine, bromine, or iodine).
Reaction Mechanism:
- The Grignard reagent acts as a nucleophile due to the electron-rich [tex]\text{R}[/tex] group.
- It attacks the electrophilic carbonyl carbon (the carbon atom double-bonded to oxygen) in acetone.
- This results in the formation of a tetrahedral alkoxide intermediate.
- The alkoxide ion, which is negatively charged, is then protonated (usually by adding a dilute acid) to form the alcohol.
Product Formation: Since acetone adds one Grignard reagent molecule, and there are two methyl groups already attached to the carbonyl carbon in acetone, the final product is a 3º alcohol. This is because three carbon groups are bonded to the central carbon atom.
Therefore, the correct option is: 3º alcohol.
