Answer :
The density of the gold is calculated to be "19,300 kg/m³".
Explanation:
Given:
Volume = 2cm³
Mass = 38.6 grams.
To Find:
Density of the gold = ?
Solution:
Density is obtained by dividing mass of the sample by its volume and it is given in the units of kg/m³.
Mass in grams is converted into kg as,
1 g = 0.001 kg
38. 6 g = [tex]\frac{38.6}{1000} = 0.0386 kg[/tex]
Now we have to convert cm³ to m³ as,
1 cm³ = 10⁻⁶ m³
2 cm³ = 2 × 10⁻⁶ m³
So Density = [tex]\frac{0.0386 k g}{2 \times 10^{-6} m^{3}}=19,300 \mathrm{kg} / \mathrm{m}^{3}[/tex]
Physical properties of Gold:
- Gold is a heavy metal.
- It is Malleable and ductile.
- It is a corrosion resistant element.
Final answer:
The density of the gold sample is 19.3 g/cm³. Other physical properties include its color, luster, and malleability.
Explanation:
The density of a substance is determined by dividing its mass by its volume. In this case, the density of the gold sample would be calculated as 38.6 grams divided by 2 cm³, which equals 19.3 g/cm³. Therefore, the density of this gold sample is 19.3 g/cm³.
Aside from density, three other physical properties of the gold sample could include its color (gold), its luster (shiny), and its malleability (ability to be shaped or formed without breaking).
Learn more about Gold Density and Physical Properties here:
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