Answer :
Final answer:
Based on the principle of conservation of energy, the velocity at 100m elevation for an object of any mass in free fall would be approximately 44.3 m/s.
Explanation:
This physics problem can be solved using the principle of conservation of energy. The energy of the object when it was at an elevation of 100m was equal to the kinetic energy it had when it struck the ground.
The equation for kinetic energy is 1/2 mv^2, where m is the mass and v is the velocity. The potential energy when the object was at 100m is mgh, where m is mass, g is the acceleration due to gravity (9.8 m/s^2), and h is the height (100m). We can set these two equal to each other to solve for the velocity at 100m (v): 1/2 * m * v^2 = m * g * h.
Solving this for v gives us v = sqrt(2 * g * h). For a 100 kg object, this results in a velocity of approximately 44.3 m/s. For a 10 kg object, the mass does not matter because it cancels out on both sides of the equation, so the velocity remains the same (44.3 m/s).
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