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------------------------------------------------ A circuit contains a battery, a 6 Ω resistor, a 15 Ω resistor, and a 27 Ω resistor connected in parallel. The total voltage of the system is 10.0 V. What is the current through the battery?

Answer :

Resistors in parallel:

R1=6 Ω

R2=15 Ω

R3=27 Ω

Total voltage = V = 10 V

To find the total R:

[tex]\frac{1}{RT}=\frac{1}{R1}+\frac{1}{R2}+\frac{1}{R3}[/tex][tex]\frac{1}{RT}=\frac{1}{6}+\frac{1}{15}+\frac{1}{27}[/tex][tex]\frac{1}{RT}=\frac{73}{270}[/tex][tex]270\cdot1=RT\cdot73[/tex][tex]\frac{270}{73}=RT[/tex]

[tex]RT=3.7[/tex]

RT=3.7Ω

Ohm's Law

V=I x R

I = V/R = 10 V / 3.7 Ω = 2.7 A

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