Answer :
In this case, the current through the 10.0Ω resistor is equal to the current through the resistor since they are in parallel.
To calculate the current through the 10.0Ω resistor in a circuit containing 10.0Ω, 12.0Ω, and 6.0Ω resistors connected in parallel with a 12V battery, we can use Ohm's Law and the rules of parallel circuits:
1. In a parallel circuit, the voltage across each resistor is the same as the voltage of the battery.
2. The total current in a parallel circuit is the sum of the currents through each resistor.
Given data:
- Resistances: R1 = 10.0Ω, R2 = 12.0Ω, R3 = 6.0Ω
- Battery voltage: V = 12V
Calculate the equivalent resistance (Req) for the parallel circuit:
1 / Req = 1 / R1 + 1 / R2 + 1 / R3
Calculate the current through each resistor using Ohm's Law:
- Current through the 10.0Ω resistor (I1): I1 = V / R1
- Current through the 12.0Ω resistor (I2): I2 = V / R2
- Current through the 6.0Ω resistor (I3): I3 = V / R3
Calculate the total current (Itotal) in the parallel circuit:
Itotal = I1 + I2 + I3
The current through the 10.0Ω resistor is equal to the current through the resistor since they are in parallel.
