Answer :
Final answer:
Using Ohm's Law, the resistance of the silver voltameter when connected to a 6 V battery with internal resistance of 2 ohms and a current of 1.5 A flowing, is calculated to be 2 ohms.
Explanation:
The resistance of the silver voltameter can be calculated using Ohm's Law, which is V = IR, where V is the potential difference, I is the current, and R is the resistance. Since the battery has an internal resistance, the potential difference across the voltameter is given by the formula V = V_emf - IR_int, where V_emf is the electromotive force (emf) of the battery and R_int is the internal resistance of the battery.
Given that the battery has an emf of 6 V, an internal resistance of 2 Ω, and a current of 1.5 A flows through the circuit, we can substitute the values into the formula:
V = 6 V - (1.5 A * 2 Ω) = 6 V - 3 V = 3 V
This potential difference of 3 V is what actually drops across the voltameter. Now, using Ohm's Law V = IR, we can solve for the resistance of the voltameter (R):
R = V / I = 3 V / 1.5 A = 2 Ω
Therefore, the resistance of the silver voltameter is 2 ohms.
