High School

A 25.0 mL sample of a saturated Ca(OH)\(_2\) solution is titrated with 0.026 M HCl. The equivalence point is reached after 37.9 mL of titrant is dispensed. Based on this data, what is the concentration (M) of the hydroxide ion?

Answer :

The concentration of the hydroxide ion can be determined by using the balanced chemical equation for the reaction between calcium hydroxide (Ca(OH)2) and hydrochloric acid (HCl).

From the equation, we can see that one mole of calcium hydroxide reacts with two moles of hydrochloric acid to form one mole of calcium chloride and two moles of water. Given that 37.9 ml of 0.026 M HCl were needed to reach the equivalence point, we can calculate the number of moles of HCl used
Moles of HCl = volume of HCl (in liters) × concentration of HCl (in moles per liter)
= 37.9 ml × (1 liter / 1000 ml) × 0.026 moles per liter
= 0.0009834 moles

Since the reaction between Ca(OH)2 and HCl occurs in a 1:2 ratio, the moles of Ca(OH)2 used will be half of the moles of HCl The volume of the Ca(OH)2 solution used was 25.0 ml, which is equivalent to 0.0250 liters. Now, we can calculate the concentration of the hydroxide ion Therefore, the concentration of the hydroxide ion is 0.01967 M.

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